j^2-9j+20=

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Solution for j^2-9j+20= equation:


Simplifying
j2 + -9j + 20 = 0

Reorder the terms:
20 + -9j + j2 = 0

Solving
20 + -9j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(4 + -1j)(5 + -1j) = 0

Subproblem 1

Set the factor '(4 + -1j)' equal to zero and attempt to solve: Simplifying 4 + -1j = 0 Solving 4 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1j = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1j = 0 + -4 -1j = 0 + -4 Combine like terms: 0 + -4 = -4 -1j = -4 Divide each side by '-1'. j = 4 Simplifying j = 4

Subproblem 2

Set the factor '(5 + -1j)' equal to zero and attempt to solve: Simplifying 5 + -1j = 0 Solving 5 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1j = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1j = 0 + -5 -1j = 0 + -5 Combine like terms: 0 + -5 = -5 -1j = -5 Divide each side by '-1'. j = 5 Simplifying j = 5

Solution

j = {4, 5}

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